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5s^2+10s-40=0
a = 5; b = 10; c = -40;
Δ = b2-4ac
Δ = 102-4·5·(-40)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-30}{2*5}=\frac{-40}{10} =-4 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+30}{2*5}=\frac{20}{10} =2 $
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